T-Test Calculator
Perform one-sample and two-sample t-tests with t-statistic and p-value.
t-Statistic
3.0945
Significant?
Yes (p<0.05)
T-Test Results
| t-Statistic | 3.0945 |
| Degrees of Freedom | 58 |
| p-value (approx) | 0.0119 |
| Mean Difference | 3.2000 |
Use the T-Test Calculator above to calculate your results. Enter your values and see instant results — all calculations run in your browser.
Disclaimer: This calculator is for informational purposes only and does not constitute tax, financial, or legal advice. Results are estimates based on the information you provide and current rates. Always consult a qualified tax professional or financial advisor for advice specific to your situation.
How It Works
The T-Test Calculator determines if there's a significant difference between the means of two groups. It's crucial for research and data analysis to validate hypotheses, such as comparing the effectiveness of two different treatments or examining if a new process improves outcomes.
This calculator typically uses either the independent samples t-test (for two unrelated groups) or the paired samples t-test (for related groups). It calculates a t-statistic using the difference between means, divided by the standard error of the difference, and then determines a p-value to assess statistical significance.
Ensure your data meets the assumptions of the t-test (e.g., normal distribution, equal variances for independent samples). A common mistake is misinterpreting a statistically significant result as a large practical effect; always consider effect size alongside the p-value.
Example: Comparing Test Scores After Two Teaching Methods
- 1 A teacher wants to see if a new teaching method improves student scores. Group A (control) used the old method, and Group B (experimental) used the new method. Input the test scores for each group into the calculator.
- 2 The calculator processes the scores for Group A and Group B, calculating their respective means, standard deviations, and the t-statistic. It then determines the p-value associated with this t-statistic.
- 3 The calculator outputs a t-statistic of, say, 2.5 and a p-value of 0.015. This p-value is below the common significance level of 0.05.
- 4 Since the p-value (0.015) is less than 0.05, we reject the null hypothesis. This suggests there is a statistically significant difference in test scores between the two teaching methods, indicating the new method likely had an effect.
Source: Khan Academy · Last updated: April 2026
Frequently Asked Questions
When should I use a t-test instead of a z-test?
What is the difference between a one-sample and two-sample t-test?
What does degrees of freedom mean in a t-test?
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